A 4-ton air conditioner removes 5.06×107 J (48,000 British thermal units) from a cold environment in

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Question

A 4-ton air conditioner removes 5.06×107
J (48,000 British thermal
units) from a cold environment in 1.00 h. (a) What energy input in joules
is necessary to do this if the air conditioner has an energy efficiency
rating ( EER ) of 12.0? (b) What is the cost of doing this if the work costs
10.0 cents per 3.60×106
J (one kilowatt-hour)? (c) Discuss whether
this cost seems realistic. Note that the energy efficiency rating ( EER ) of
an air conditioner or refrigerator is defined to be the number of British
thermal units of heat transfer from a cold environment per hour divided by
the watts of power input.

 

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